1890 Idaho gubernatorial election

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1890 Idaho gubernatorial election
Flag of Idaho.svg
1 October 1890 1892  
  Georgelshoup.jpg No image.svg
Nominee George L. Shoup Benjamin Wilson
Party Republican Democratic
Popular vote10,262 7,948
Percentage56.35%43.65%

1890 Idaho gubernatorial election results map by county.svg
County results
Shoup:     50–60%     60–70%
Wilson:     50–60%

Governor before election

George L. Shoup (Territorial)
Republican

Elected Governor

George L. Shoup
Republican

The 1890 Idaho gubernatorial election was held on 1 October 1890, in order to elect the first Governor of Idaho upon Idaho acquiring statehood in July 1890. Incumbent Republican Governor of the Idaho Territory George L. Shoup defeated Democratic nominee Benjamin Wilson. [1]

Contents

General election

On election day, 1 October 1890, Republican nominee George L. Shoup won the election by a margin of 2,314 votes against his opponent Democratic nominee Benjamin Wilson, thereby retaining Republican control over the new office of Governor. Shoup was sworn in as the first Governor of the new state of Idaho on 8 December 1890. [2]

Results

Idaho gubernatorial election, 1890
PartyCandidateVotes%
Republican George L. Shoup (incumbent [lower-alpha 1] ) 10,262 56.35%
Democratic Benjamin Wilson 7,94843.65%
Total votes18,210 100.00%
Republican hold

Notes

  1. Incumbent governor of Idaho Territory.

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References

  1. "George L. Shoup". National Governors Association. Retrieved May 12, 2023.
  2. "ID Governor". ourcampaigns.com. September 26, 2005. Retrieved May 12, 2023.