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Elections in Louisiana |
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Government |
The 1824 United States presidential election in Louisiana took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose five representatives, or electors to the Electoral College, who voted for president and vice president.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. Louisiana cast three electoral votes for Andrew Jackson and two for John Quincy Adams.
1824 United States presidential election in Louisiana [1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Andrew Jackson | 3 | |||
Democratic-Republican | John Quincy Adams | 2 | |||
Democratic-Republican | Henry Clay | 0 | |||
Democratic-Republican | William H. Crawford | 0 | |||
Totals | 5 | ||||
The 1824 United States presidential election was the tenth quadrennial presidential election. It was held from Tuesday, October 26 to Wednesday, December 1, 1824. Andrew Jackson, John Quincy Adams, Henry Clay and William Crawford were the primary contenders for the presidency. The result of the election was inconclusive, as no candidate won a majority of the electoral vote. In the election for vice president, John C. Calhoun was elected with a comfortable majority of the vote. Because none of the candidates for president garnered an electoral vote majority, the U.S. House of Representatives, under the provisions of the Twelfth Amendment, held a contingent election. On February 9, 1825, John Quincy Adams was elected as president without getting the majority of the electoral vote or the popular vote, being the only president to do so.
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