1860 United States presidential election in Indiana

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1860 United States presidential election in Indiana
Flag of Indiana.svg
  1856 November 6, 1860 1864  
  Abraham Lincoln by Alexander Hesler, 1860-restored (cropped).png Senator Stephen A. Douglas (edited).png
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote130
Popular vote139,033115,509
Percentage51.09%42.44%

Indiana Presidential Election Results 1860.svg
County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Indiana took place on November 6, 1860, as part of the 1860 United States presidential election. Indiana voters chose 13 representatives, or electors, to the Electoral College, who voted for president and vice president.

Contents

Indiana was won by Republican nominee Representative Abraham Lincoln of Illinois and his running mate Senator Hannibal Hamlin of Maine. They defeated the Democratic nominee Senator Stephen A. Douglas of Illinois] and his running mate 41st Governor of Georgia Herschel V. Johnson. Lincoln won the state by a margin of 8.65%.

Results

1860 United States presidential election in Indiana [1]
PartyCandidateVotes%
Republican Abraham Lincoln 139,033 51.09%
Democratic Stephen A. Douglas 115,50942.44%
Southern Democratic John C. Breckinridge 12,2954.52%
Constitutional Union John Bell 5,3061.95%
Total votes272,143 100%

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References

  1. "1860 Presidential Election Results Indiana".