1891 Iowa gubernatorial election

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1891 Iowa gubernatorial election
Flag of Iowa.svg
  1889 November 3, 1891 1893  
  Horace Boies signed.jpg 3x4.svg
Nominee Horace Boies Herman C. Wheeler
Party Democratic Republican
Popular vote207,594199,381
Percentage49.40%47.45%

Governor before election

Horace Boies
Democratic

Elected Governor

Horace Boies
Democratic

The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Herman C. Wheeler with 49.40% of the vote.

Contents

General election

Candidates

Major party candidates

Other candidates

Results

1891 Iowa gubernatorial election [1]
PartyCandidateVotes%±%
Democratic Horace Boies (incumbent) 207,594 49.40%
Republican Herman C. Wheeler199,38147.45%
Populist A. J. Westfall12,3032.93%
Prohibition Isaac T. Gibson9150.22%
Majority8,213
Turnout
Democratic hold Swing

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References

  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 9, 2020.