1940 United States presidential election in Delaware

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1940 United States presidential election in Delaware
Flag of Delaware.svg
  1936 November 5, 1940 [1] 1944  

All 3 Delaware votes to the Electoral College
  FDRoosevelt1938.png WendellWillkie.jpg
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote30
Popular vote74,59961,440
Percentage54.70%45.05%

Delaware Presidential Election Results 1940.svg
County Results
Roosevelt
  50-60%


President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three [2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Contents

Delaware was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote. [3] [4]

Results

1940 United States presidential election in Delaware
PartyCandidateVotes%
Democratic Franklin D. Roosevelt (inc.) 74,599 54.70%
Republican Wendell Willkie 61,44045.05%
Write-in 3350.25%
Total votes136,334 100%

Results by county

CountyDemRepOth
Kent9,2268,07948
New Castle52,16741,508261
Sussex13,20611,85326
STATEWIDE74,59961,440335

See also

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References

  1. "United States Presidential election of 1940 - Encyclopædia Britannica" . Retrieved August 20, 2018.
  2. "1940 Election for the Thirty-ninth Term (1941-45)" . Retrieved August 20, 2018.
  3. "1940 Presidential General Election Results - Delaware" . Retrieved August 20, 2018.
  4. "The American Presidency Project - Election of 1940" . Retrieved August 20, 2018.