1908 United States presidential election in Delaware

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1908 United States presidential election in Delaware
Flag of Delaware.svg
  1904 November 3, 1908 1912  
  William Howard Taft, Bain bw photo portrait, 1908.jpg Unsuccessful 1908.jpg
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote30
Popular vote25,01422,055
Percentage52.10%45.94%

Delaware Presidential Election Results 1908.svg
County Results
Taft
  40-50%
  50-60%

The 1908 United States presidential election in Delaware took place on November 3, 1908. All contemporary 46 states were part of the 1908 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Contents

Delaware was won by the Republican nominees, former Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern. Taft won the state by a margin of 6.16%.

Bryan had previously lost Delaware to William McKinley in both 1896 and 1900.

Results

1908 United States presidential election in Delaware [1]
PartyCandidateVotesPercentageElectoral votes
Republican William Howard Taft 25,01452.10%3
Democratic William Jennings Bryan 22,05545.94%0
Prohibition Eugene W. Chafin 6701.40%0
Social Democratic Eugene V. Debs 2390.50%0
Independence Thomas L. Hisgen 290.06%0
Totals48,007100.00%3
Voter turnout

Results by county

CountyWilliam Howard Taft
Republican
William Jennings Bryan
Democrat
Various candidates
Others
Total
votes
 %# %# %#
Kent 49.75%4,15849.00%4,0951.25%1048,357
New Castle 52.29%14,97945.26%12,9642.45%70128,644
Sussex 53.25%5,87045.48%5,0131.27%14011,023

See also

Notes

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    References