1880 Rhode Island gubernatorial election

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1880 Rhode Island gubernatorial election
Flag of Rhode Island (1877-1882).png
  1879 April 7, 1880 1881  
  Alfred Henry Littlefield.jpg No image.svg No image.svg
Nominee Alfred H. Littlefield Horace A. Kimball Albert C. Howard
Party Republican Democratic Independent Republican
Popular vote10,2247,4405,047
Percentage44.82%32.62%22.13%

Governor before election

Charles C. Van Zandt
Republican

Elected Governor

Alfred H. Littlefield
Republican

The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.

Contents

General election

Candidates

Major party candidates

Other candidates

Results

1880 Rhode Island gubernatorial election [1]
PartyCandidateVotes%±%
Republican Alfred H. Littlefield 10,224 44.82%
Democratic Horace A. Kimball7,44032.62%
Independent Republican Albert C. Howard 5,04722.13%
Majority2,784
Turnout
Republican hold Swing

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References

  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN   9780871879967 . Retrieved October 27, 2020.